Singles
2019 Kiskút Open II
Champion	Danka Kovinić
Runner-up	Irina-Camelia Begu
Score	6–4, 3–6, 6–3

This was the first edition of the tournament.^[1]

Danka Kovinić won the title, defeating Irina-Camelia Begu in the final, 6–4, 3–6, 6–3.

Seeds

Draw

Finals

	Semifinals							Final
	5	Katarina Zavatska	0	1r
	3	Danka Kovinić	6	4
								3	Danka Kovinić	6	3	6
								4	Irina-Camelia Begu	4	6	3
	4	Irina-Camelia Begu	6	6
		Verónica Cepede Royg	3	1

Top half

	First round							Second round							Quarterfinals							Semifinals
	1	P Badosa	6	0	1
	Q	V Kan	4	6	6			Q	V Kan	1	2
	Q	M Bulgaru	4	6	3				K Juvan	6	6
		K Juvan	6	4	6											K Juvan	1	4
	Q	M Chwalińska	1	1											5	K Zavatska	6	6
	SE	I Bara	6	6				SE	I Bara	0	0r
	WC	F Stollár	4	2				5	K Zavatska	6	1
	5	K Zavatska	6	6																		5	K Zavatska	0	1r
	3	D Kovinić	6	6																		3	D Kovinić	6	4
		R Šramková	3	0				3	D Kovinić	6	2	6
		K Kučová	5	5					V Tomova	4	6	3
		V Tomova	7	7											3	D Kovinić	77	6
	Q	D Drahota-Szabó	4	67											8	T Korpatsch	65	1
	Q	M Benoît	6	79				Q	M Benoît	1	3
	WC	A Bondár	2	4				8	T Korpatsch	6	6
	8	T Korpatsch	6	6

Bottom half

	First round							Second round							Quarterfinals							Semifinals
	7	J Paolini	6	7
		I Shinikova	2	5				7	J Paolini	3	77	6
	PR	S Celik	4	1				Q	IG Ghioroaie	6	64	3
	Q	IG Ghioroaie	6	6											7	J Paolini	67	2
	Q	A Cadanțu	6	0											4	I-C Begu	79	6
	Q	G Arn	0	0r				Q	A Cadanțu	3	3
		B Haas	62	0r				4	I-C Begu	6	6
	4	I-C Begu	77	1																		4	I-C Begu	6	6
	6	PM Țig	4	1																			V Cepede Royg	3	1
		M Trevisan	6	6					M Trevisan	64	6	6
	WC	D Gálfi	3	6	4				J Čepelová	77	3	4
		J Čepelová	6	3	6											M Trevisan	3	0
	WC	RL Jani	4	2												V Cepede Royg	6	6
		V Cepede Royg	6	6					V Cepede Royg	4	6	77
		K Kawa	5	6	3			2	A Bolsova	6	3	64
	2	A Bolsova	7	2	6

References

• Main Draw